1001. A+B Format (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

 

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

#include <iostream>

#include <stack>

#include <stdlib.h>

using namespace std;

//题意很简单，就是货币格式表示法

int main()

{

int a,b;

cin>>a>>b;

stack<int> sta;

int c = a+b;

if(c<0)cout<<"-";//如果结果是复数，就先输出一个负号。

if(c==0) cout<<0;//如果结果是0，就直接输出

while(c!=0)

{

int temp = c%10;

c/=10;

sta.push(temp);

}//从个位开始依次入栈

int first=sta.size()%3;

int count=0;

while(!sta.empty())//出栈操作

{

cout<<abs(sta.top());

count++;sta.pop();

if(count==first&&sta.size()>0) {cout<<",";first = 10;count=0;}

if(count==3&&sta.size()!=0){cout<<",";count=0;}

}

}